e) div( div F), (f) curl( curl F), (g) div(curl(grad f) ) . the part of the plane2x + 3y+ z =6 that lies in the first octant.
![SOLVED: points) Match the vector fields: 1. div(F)-2,rot(F)= E divF)–2, rot(F)-1 3. div(F)-0, rot(F) = -2 4. div(F)-0, rot(F) = divF)–2, rot(F)-1 6. div(F)-0, rot(F) = SOLVED: points) Match the vector fields: 1. div(F)-2,rot(F)= E divF)–2, rot(F)-1 3. div(F)-0, rot(F) = -2 4. div(F)-0, rot(F) = divF)–2, rot(F)-1 6. div(F)-0, rot(F) =](https://cdn.numerade.com/ask_images/18f0b68a1eef4cd49d1482d7416ea3fa.jpg)
SOLVED: points) Match the vector fields: 1. div(F)-2,rot(F)= E divF)–2, rot(F)-1 3. div(F)-0, rot(F) = -2 4. div(F)-0, rot(F) = divF)–2, rot(F)-1 6. div(F)-0, rot(F) =
![SOLVED: Show that for a twice continuously differentiable vector field 'v(c) U : R? R? I + U2(€) U3(€ div (rot ( )) =0 applies H1+T2 + T2 T3 T1 +T1T3 LT2 SOLVED: Show that for a twice continuously differentiable vector field 'v(c) U : R? R? I + U2(€) U3(€ div (rot ( )) =0 applies H1+T2 + T2 T3 T1 +T1T3 LT2](https://cdn.numerade.com/ask_images/2d5e37752ebe42db8d21202ac48c8cc9.jpg)
SOLVED: Show that for a twice continuously differentiable vector field 'v(c) U : R? R? I + U2(€) U3(€ div (rot ( )) =0 applies H1+T2 + T2 T3 T1 +T1T3 LT2
![differential geometry - Motivation for constructing $F$ s.t. $\ker(\text{ curl}) \subset \text{Im}(\text{grad})$, $\ker(\text{div}) \subset \text{Im}(\text{curl})$ - Mathematics Stack Exchange differential geometry - Motivation for constructing $F$ s.t. $\ker(\text{ curl}) \subset \text{Im}(\text{grad})$, $\ker(\text{div}) \subset \text{Im}(\text{curl})$ - Mathematics Stack Exchange](https://i.stack.imgur.com/hUeLZ.png)